SOLUTION: Marsha and Kan both invested money on March 1, 2007. Marsha invested $9,000 at Bank A where the interest was compounded quarterly. Jan invested $6,000 at Bank B where the interest

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Question 911762: Marsha and Kan both invested money on March 1, 2007. Marsha invested $9,000 at Bank A where the interest was compounded quarterly. Jan invested $6,000 at Bank B where the interest was compounded continuously. On March 1, 2012, Marsha had a balance of $11,789.68 while Jan had a balance of $7,504.50. What was the interest at each bank?
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Marsha and Kan both invested money on March 1, 2007.
Marsha invested $9,000 at Bank A where the interest was compounded quarterly.
Jan invested $6,000 at Bank B where the interest was compounded continuously.
On March 1, 2012, Marsha had a balance of $11,789.68 while Jan had a balance of $7,504.50.
What was the interest at each bank?
:
From the information given, we know both had money invested for 5 yrs
:
M
9000%281%2B%28r%2F4%29%29%5E%285%2A4%29 = 11789.68
%281%2B%28r%2F4%29%29%5E20 = 11789.68%2F9000
use logs here
log%28%281%2B%28r%2F4%29%29%5E20%29 = log%2811789.68%2F9000%29
log%28%281%2B%28r%2F4%29%29%5E20%29 = .1172595
log%28%281%2B%28r%2F4%29%29%29 = 1172595%2F20
log%281%2B%28r%2F4%29%29 = .005862975
find the antilog
1 + r%2F4 = 1.0136
r%2F4 = 1.0136 - 1
r%2F4 = .0136
mult both sides fy 4
r = .054366 ~ 5.44% interest
:
J
6000%2Ae%5E%285r%29 = 7504.50
e%5E%285r%29 = 7504.50%2F6000
use natural logs here, ln of e = 1, so we have a simple equation
5r = ln%287504.50%2F6000%29
5r = .21046
r = .2237%2F5
r = .04475 ~ 4.475% interest
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