SOLUTION: Lisa spent $16.18 for some cans of dog food costing 79 cents each and some cans of <b>dog</b> <i>changed to cat</i> food costing 69 cents each. She bought two more cans of cat food

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Lisa spent $16.18 for some cans of dog food costing 79 cents each and some cans of <b>dog</b> <i>changed to cat</i> food costing 69 cents each. She bought two more cans of cat food      Log On

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Question 907244: Lisa spent $16.18 for some cans of dog food costing 79 cents each and some cans of dog changed to cat food costing 69 cents each. She bought two more cans of cat food than dog food. How many cans of each did she buy?

Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
.79x + .69(x+2) = 16.18
NOTE: I'm assuming that your question should read 'dog' then 'cat' instead of both dog.
Distribute
.79x + .69x + 1.38 = 16.18
Subtract 1.38 from each side
1.48x = 14.8
Divide each side by 1.48
x = 10 cans of dog food
If 10 cans of dog food, then 12 cans of cat food
10 * .79 = $7.90
12 * .69 = $8.28
$7.90 + $8.28 = $16.18