SOLUTION: The intensity of light varies inversely a the square of the distance from the light source. If the intensity from a light source 5 feet away is 8 lumens, what is the intensity at a

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Question 906415: The intensity of light varies inversely a the square of the distance from the light source. If the intensity from a light source 5 feet away is 8 lumens, what is the intensity at a distance of 2 feet?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The intensity of light varies inversely a the square of the distance from the light source. If the intensity from a light source 5 feet away is 8 lumens, what is the intensity at a distance of 2 feet?
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I = k/d^2
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Solve for "k":
8 = k/5^2
k = 200
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Equation:
I = 200/d^2
I = 200/2^2 = 200/4 = 50 lumens
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Cheers,
Stan H.
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