SOLUTION: The height of a ball that is thrown upward is given by
h(t) = {{{ 16t^2 + 68t }}}
where t is in seconds and height is in feet. The maximum height the ball reaches is ____ f
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-> SOLUTION: The height of a ball that is thrown upward is given by
h(t) = {{{ 16t^2 + 68t }}}
where t is in seconds and height is in feet. The maximum height the ball reaches is ____ f
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Question 906158: The height of a ball that is thrown upward is given by
h(t) =
where t is in seconds and height is in feet. The maximum height the ball reaches is ____ feet, when t = ____ seconds. Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! The equation should be:
The minus sign is for the
downward pull of gravity
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The formula for
is:
where:
Now find
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The max height is 72.25 ft
when the time is 2.125 sec
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Here's the plot:
