SOLUTION: At 9:45am Margie threw a ball upwards while standing on a platform 65 ft above the ground. The trajectory after t seconds follows the equation: h(-0.7t^2 +56t+65. A. What will b

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Question 905993: At 9:45am Margie threw a ball upwards while standing on a platform 65 ft above the ground. The trajectory after t seconds follows the equation: h(-0.7t^2 +56t+65.
A. What will be the maximum height of the ball?
B. How long will it take the ball to reach its maximum height?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
h = -0.7t^2 +56t+65 = -.7(t -40)^2 + 1120 + 65
A is 1185 max
B is 40sec