SOLUTION: If I want to make the perfect 12 oz. cup of chocolate milk, it requires that the mixture is 42% Syrup. What I have now is 8 oz. of a milk/syrup mixture that I know contains 30% sy

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Question 88989: If I want to make the perfect 12 oz. cup of chocolate milk, it requires that the mixture is 42% Syrup. What I have now is 8 oz. of a milk/syrup mixture that I know contains 30% syrup. What must the syrup concentration be in the remaining mixture that I must add in order to achieve perfection?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If I want to make the perfect 12 oz. cup of chocolate milk, it requires that the mixture is 42% Syrup. What I have now is 8 oz. of a milk/syrup mixture that I know contains 30% syrup. What must the syrup concentration be in the remaining mixture that I must add in order to achieve perfection?
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Final mixture DATA:
Amt of mix = 12 oz. ; amt of syrup = 0.42(12) = 5.04 oz
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Have now DATA:
Amt of mix = 8 oz. ; amt of syrup = 0.30(8) = 2.4 oz
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Misture to be added DATA:
Amt of mix = 12-8 = 4 oz ; amt of syrup = 4x where x is the percent.
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EQUATION:
syrup + syrup = syrup
2.4 + 4x = 5.04
4x = 2.64x = .66
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66% of the added mixture must be syrup
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Cheers,
Stan H.