a person has certain no of cows &birds. they have 172eyes & 344 legs.how meny cows& birds does he have
Two ways to do it: with and without algebra:
Without algbra:
Since there are 172 eyes, there are 86 animals. If they were all cows there
would also be 86x4 = 344 legs. And that's how many there are, So they are all
cows. 86 cows and no birds.
So the problem is wrong for stating that he has some birds. I suppose the trick
is that 0 birds is a number of birds, since 0 is a number.
In that case I own a number of gold mines, yachts, mansions, and Ferraris.
That's because I have won the lottery a number of times. Hahaha J
With algebra:
2c + 2b = 172
4c + 2b = 344
Subtract the first equation from the second and get
2c = 172
c = 86
Substituting in the first:
2c + 2b = 172
2(86) + 2b = 172
172 + 2b = 172
2b = 0
b = 0
Edwin
