SOLUTION: "The width of a rectangular room is 10 feet less than its length. The area of the room is 375 square feet. Find the width and length of the room." I started out with 2L+2(L-

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: "The width of a rectangular room is 10 feet less than its length. The area of the room is 375 square feet. Find the width and length of the room." I started out with 2L+2(L-      Log On

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Question 881459: "The width of a rectangular room is 10 feet less than its length. The area of the room is 375 square feet. Find the width and length of the room."


I started out with 2L+2(L-10)=357
2L+2L-20=357
4L=377
4L/4=377/4
L=94.25 square feet.
I don't feel like this is the right answer. I appreciate the help! Thanks!

Found 2 solutions by richwmiller, JoelSchwartz:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Did you check it?
if 94.25 is the length what is the width?
84.25-10 is the width
94.25*84.25=7940.5625
you used the formula for circumference not area!
you want L*w=375
L*(L-10)=375
L^2-10L-375=0

Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression x%5E2-10x-375, we can see that the first coefficient is 1, the second coefficient is -10, and the last term is -375.



Now multiply the first coefficient 1 by the last term -375 to get %281%29%28-375%29=-375.



Now the question is: what two whole numbers multiply to -375 (the previous product) and add to the second coefficient -10?



To find these two numbers, we need to list all of the factors of -375 (the previous product).



Factors of -375:

1,3,5,15,25,75,125,375

-1,-3,-5,-15,-25,-75,-125,-375



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to -375.

1*(-375) = -375
3*(-125) = -375
5*(-75) = -375
15*(-25) = -375
(-1)*(375) = -375
(-3)*(125) = -375
(-5)*(75) = -375
(-15)*(25) = -375


Now let's add up each pair of factors to see if one pair adds to the middle coefficient -10:



First NumberSecond NumberSum
1-3751+(-375)=-374
3-1253+(-125)=-122
5-755+(-75)=-70
15-2515+(-25)=-10
-1375-1+375=374
-3125-3+125=122
-575-5+75=70
-1525-15+25=10




From the table, we can see that the two numbers 15 and -25 add to -10 (the middle coefficient).



So the two numbers 15 and -25 both multiply to -375 and add to -10



Now replace the middle term -10x with 15x-25x. Remember, 15 and -25 add to -10. So this shows us that 15x-25x=-10x.



x%5E2%2Bhighlight%2815x-25x%29-375 Replace the second term -10x with 15x-25x.



%28x%5E2%2B15x%29%2B%28-25x-375%29 Group the terms into two pairs.



x%28x%2B15%29%2B%28-25x-375%29 Factor out the GCF x from the first group.



x%28x%2B15%29-25%28x%2B15%29 Factor out 25 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%28x-25%29%28x%2B15%29 Combine like terms. Or factor out the common term x%2B15



===============================================================



Answer:



So x%5E2-10%2Ax-375 factors to %28x-25%29%28x%2B15%29.



In other words, x%5E2-10%2Ax-375=%28x-25%29%28x%2B15%29.



Note: you can check the answer by expanding %28x-25%29%28x%2B15%29 to get x%5E2-10%2Ax-375 or by graphing the original expression and the answer (the two graphs should be identical).


the solver doesn't like L
discard negative answers
x-25=0
L=25
W=15

Answer by JoelSchwartz(130) About Me  (Show Source):
You can put this solution on YOUR website!
w=L-10
A=Lw
375=Lw
375=L(L-10)
375=L^2-10L
L^2-10L-375=0
10/2+-((100-4(-375))^(1/2))/2
5+-20
25
L=25
w=15