SOLUTION: could some one please help me with this problem.
A bus leaves a station at 1 p.m.;taveling west at an average rate of 44mi/h.One hour later a second bus leaves the same station
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A bus leaves a station at 1 p.m.;taveling west at an average rate of 44mi/h.One hour later a second bus leaves the same station
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Question 88058: could some one please help me with this problem.
A bus leaves a station at 1 p.m.;taveling west at an average rate of 44mi/h.One hour later a second bus leaves the same station,traveling east at a rate of 48mi/h.At what time will the two buses be 274 mi apart? Answer by maxchuie(2) (Show Source):
You can put this solution on YOUR website! you can use the formula {d=rt}
44x+48(x-1)=274
44x+48x-48=274
9x-48+48=274+48
92x=322
x=3 1/2
1:00pm +3 1/2 hrs = 4:30pm
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