Question 86826: A box contains 4 blue balls 5 green balls and 3 yellow balls. You randomly select 3 balls, one at a time, from the box without replacing a selected ball. What is the probability of selecting a blue, a green, a yellow in that order?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A box contains 4 blue balls 5 green balls and 3 yellow balls. You randomly select 3 balls, one at a time, from the box without replacing a selected ball. What is the probability of selecting a blue, a green, a yellow in that order?
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P(blue)*P(green)*P(yellow)
= 4/12 * 5*11 * 3/10
= 5/110
= 1/22
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Cheers,
Stan H.
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