SOLUTION: the of a rectangle is 4 feet less than twice the width.the area is 160 squ the are feet. find the length andd width of the rectangle and diagonal

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: the of a rectangle is 4 feet less than twice the width.the area is 160 squ the are feet. find the length andd width of the rectangle and diagonal      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 866379: the of a rectangle is 4 feet less than twice the width.the area is 160 squ the are feet. find the length andd width of the rectangle and diagonal
Found 2 solutions by josgarithmetic, ewatrrr:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
L=-4%2B2w---from description
160=wL=w%282w-4%29-----ready to find w.


Note that the diagonal cuts the rectangle into two congruent (equal size and shape) right triangles.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

A = Lw = (2w-4)w = 160 

w^2 -2w - 80 = 0

(w + 8)(w-10) = 0   (Tossing out the negative solution for unit measure)

         w = 10ft  and L = 16ft   20-4