SOLUTION: I would really appreciate some help with a word problem that has been nagging at me. The questions is exactly like this: One aduly and 10 children are in an elevator. If the

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Question 86366This question is from textbook The Official SAT
: I would really appreciate some help with a word problem that has been nagging at me.
The questions is exactly like this:
One aduly and 10 children are in an elevator. If the adult's weight is 4 times the average (arithmetic mean) weight of the children, then the adult's weight is what fraction of the total weight of the 11 people in the elevator?
I would appreciate the help. Thanks! This question is from textbook The Official SAT

Answer by chitra(359) About Me  (Show Source):
You can put this solution on YOUR website!
It is given that there are 11 people in the elevator, which includes one adult and 10 children.

Let the adult weight be "x" and the child weight be "y".

It is said that the adult weight is 4 times higher than that of the childs weight.

Therfore adults weight = 4y and childs weight = y

Sum of their weights ==> 4y + y = 11

==> 5y = 11

==> y+=+11%2F5

Now by substituting the y value, for x, we get the weight of the adult.

x = 4y

==> +x+=+4%2811%2F5%29+

==> +x+=+44%2F5+


Hence, the weight of the adult is 44/5

Thus, the solution.

Regards