SOLUTION: Jess is running around a circular track, one lap every 40 seconds. Cameron is also running at a constant speed around the same track, but in the opposite direction. They meet every
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: Jess is running around a circular track, one lap every 40 seconds. Cameron is also running at a constant speed around the same track, but in the opposite direction. They meet every
Log On
Question 862840: Jess is running around a circular track, one lap every 40 seconds. Cameron is also running at a constant speed around the same track, but in the opposite direction. They meet every 15 seconds. How many seconds does it take Cameron to do one lap? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Jess is running around a circular track, one lap every 40 seconds.
Cameron is also running at a constant speed around the same track, but in the opposite direction.
They meet every 15 seconds. How many seconds does it take Cameron to do one lap?
:
let c = C's time to make one lap
:
In 15 sec, J had run 15/40 or 3/8 of a lap, therefore C has run 5/8 of a lap in the same time.
We can write the relationship: 3:5
An inverse relationship =
Cross multiply
5c = 3(40)
c = 120/5
c = 24 seconds is C's lap time
