Question 824808: if carter peak height at the basket of leaped for a dunk and reached a 1.07m, what was his upward velocity in meters per second at the monent his feet left the floor: and find the amount of time he was in the air?
v1^2=v^20 +2gS
S=1/2 gt^2+v0t
Answer by KMST(5328)   (Show Source):
You can put this solution on YOUR website! IF THIS IS PHYSICS:
Since movement is along a straight line, we can indicate direction (upwards or downwards) by assigning a positive sign to measures of displacement, velocity, and acceleration in one direction. Displacement, velocity, and acceleration in the opposite direction are assigned a negative sign. It does not matter which direction is taken as the positive direction, as long as you do not forget halfway through the problem.
I say upwards is the positive direction.
I say position 0 is the start of the leap,
and position 1 is at the top of the leap.
 is the positive displacement of the leaper (distance from floor to feet) at the highest point of the leap, position 1.
 is the time rising to the top of the leap,
  is the acceleration (negative because it is downwards),
 is the velocity at the start of the leap, position 0.
 is the velocity at the top of the leap, position 1.
IF THIS IS JUST MATH:
You've been given two magical formulas:
 and  .
Since you do not know , you'll have to use
Substituting the values listed above, with meters and seconds in the units,
 
IF THIS IS PHYSICS:
 and
do not seem useful by themselves
 is the average velocity, so  .
From there we can get to , but we can also get to .
--> -->
Substituting  for into we get
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