SOLUTION: The length of a rectangle is eight inches more than its width. If four inches are taken off from both width's and twelve inches are removed from both lengths the figure becomes a s

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: The length of a rectangle is eight inches more than its width. If four inches are taken off from both width's and twelve inches are removed from both lengths the figure becomes a s      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 81573: The length of a rectangle is eight inches more than its width. If four inches are taken off from both width's and twelve inches are removed from both lengths the figure becomes a square with the area of 225 square inches. What are the dimensions of the original figure?
Found 2 solutions by rajagopalan, JoelSchwartz:
Answer by rajagopalan(174) About Me  (Show Source):
You can put this solution on YOUR website!
L of rectangle is 8in more than its w
If 4in are taken off from the width the figure becomes a square.
area of 225 square in.
*********
Modified figure area 225 sq in
Side of the square = 15
So width of rectangle=15+8=23 in
So original fig has Length = 23 in
Width =8 in.
OKAY.

Answer by JoelSchwartz(130) About Me  (Show Source):
You can put this solution on YOUR website!
L=8+w
w-4=s
A=s^2
225=s^2
15=s
w-4=15
w=19
L=8+19
L=27