SOLUTION: Jane is thinking of a number between -10 and 10. If you multiply Jane’s number by -2, then subtract 2, the result is greater than 6. Is Jane's number greater than -4 or less than

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Question 771585: Jane is thinking of a number between -10 and 10. If you multiply Jane’s number by -2, then subtract 2, the result is greater than 6. Is Jane's number greater than -4 or less than -4?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The fact that the number is between -10 and 10 does not matter for the problem.
However, if you had to guess the number, knowing that it is between -10 and 10 would improve your chances.

THE GUESSER SOLUTION:
Could it be 0?
-2%2A0-2=0-2=-2 and that is not greater than 6, so 0 cannot be Jane's number.
Since 0 is greater than -4, and it does not work, the solution must be that
Jane's number is less than -4

THE ALGEBRA SOLUTION:
x= the number Jane is thinking
-2x= the number Jane is thinking multiplied times -2
-2x-2= the result of multiplying Jane's number times -2, and then subtracting 2
-2x-2%3E6 --> -2%28x%2B1%29%3E6 (taking out the common factor -2)
-2%28x%2B1%29%3E6 --> -2%28x%2B1%29%2F%28-2%29%3C6%2F%28-2%29 (because on multiplying/dividing by a negative number we are flipping around the number line, and that flips the inequality sign, see NOTE below)
-2%28x%2B1%29%2F%28-2%29%3C6%2F%28-2%29 --> x%2B1%3C-3 (just simplifying)
x%2B1%3C-3 --> x%2B1-1%3C-3-1 --> highlight%28x%3C-4%29 (subtracting 1 from both sides and simplifying)
So Jane's number is less than -4.

NOTE:
number_line%28+600%2C+-10%2C+10%2C+-4%2C+-6%2C+-8%2C+5+%29 -8%3C-6%3C-4%3C5
The numbers to the left (of -4, or of any other number) are less, and the numbers to the right are more.
Multiplying times -1 means changing the signs off all the numbers, so we end up with
number_line%28+600%2C+-10%2C+10%2C+4%2C+6%2C+8%2C+-5+%29 -5%3C4%3C6%3C8 or 8%3E6%3E4%3E-5
If one number was less than (to the left of) a certain number, after multiplying both numbers times -1, the order is reversed, so the signs change from < to > and from > to <.