Question 753297: And gave bill and clare as much money as each had. (This means if clare started with $5 and bill started with $3, ana would give clare $5 and bill $3). Then bill gave ana and clare as much money as each had. Then clare gave ana and bill as much money as each had. At the close of these exchanges, ana, clare, and bill each had $24.00. How much money did each start with?
Have to work this problem out by working backwards...please help!
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
At the very end, the amounts of money are:
A -- 24
B -- 24
C -- 24
If A and B received as much as they had just prior to the last transaction, they must each have received 12 and they must have received it from C, so at the end of the previous step, the situation must have been:
A -- 12 (24 minus 12)
B -- 12 (24 minus 12)
C -- 48 (24 plus 12 plus 12)
Before that, A and C got half of what they had above from B, so:
A -- 6 (12 minus 6)
B -- 42 (12 plus 6 plus 24)
C -- 24 (48 minus 24)
And initially, B and C got half of what they had above from A, so:
A -- 39 (6 plus 21 plus 12)
B -- 21 (42 minus 21)
C -- 12 (24 minus 12)
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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