SOLUTION: Please help!
Two boys weighing 140 and 105lb, respectively, balance each other on a see-saw sitting 7 ft. apart. What is the distance of each from the pivot point?
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Two boys weighing 140 and 105lb, respectively, balance each other on a see-saw sitting 7 ft. apart. What is the distance of each from the pivot point?
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Question 74219: Please help!
Two boys weighing 140 and 105lb, respectively, balance each other on a see-saw sitting 7 ft. apart. What is the distance of each from the pivot point?
Thank You! Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Let x=distance from 140 lb boy and y=distance from 105 lb boy Set up a ratio between the distances and the weights Multiply both sides by xy to get rid of the fraction Here's the sum of the distances Solve for y plug this into x and solve
So the 140 pound boy is 4 ft away from the pivot.
So the 105 pound boy is 3 ft away.