Question 731595: When the circus came to town last year, they hired general labors at $70 per day and mechanics at $90 per day. They paid $1950 foe this temporary help for one day. This year they hired exactly the same number of people of each type, but they paid $80 for general labors and $100 for mechanics for one day. This year they paid $2200 for temporary help. How many general laborers did they hire? How many mechanics did they hire?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! When the circus came to town last year, they hired general labors
at $70 per day and mechanics at $90 per day.
They paid $1950 for this temporary help for one day.
This year they hired exactly the same number of people of each type,
but they paid $80 for general labors and $100 for mechanics for one day.
This year they paid $2200 for temporary help.
How many general laborers did they hire?
How many mechanics did they hire?
:
Let g = no. of general laborers
Let m = no. of mechanics
:
Write an equation for each year
70g + 90m = 1950
simplify, divide by 10
7g + 9m = 195
:
and this year:
80g + 100m = 2200
simplify, divide by 20
4g + 5m = 110
:
multiply the 1st simplified equation by 4, the 2nd by 7
28g + 36m = 780
28g + 35m = 770
------------------subtraction eliminates g, find m
1m = 10 mechanics
then
4g + 5(10) = 110
4g = 110 - 50
4g = 60
g = 60/4
g = 15 gen laborers.
:
;
Check solutions in the 1st original equation
70g + 90m = 1950
g=15; m=10
70(15) + 90(10) =
1050 + 900 = 1950; confirms our solutions
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