Question 71899: One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number. Answer by psbhowmick(878) (Show Source):
You can put this solution on YOUR website! Let the first number = x.
Then the other number = 12 more than 'x' = (x+12).
Clearly, 'x' is the smaller number and (x+12) is the larger.
So the sum of the smaller number and twice the larger number = x + 2(x + 12) = 39
i.e. x + 2(x + 12) = 39
x + 2x + 2*12 = 39
3x + 24 = 39
3x = 39 - 24
3x = 15
x = 15/3
x = 5
So the smaller number = x = 5 and the larger number = (x + 12) = 5 + 12 = 17
