SOLUTION: Puzzle Time : There are 4 doors in a video game parlour. (door no. 1, 2, 3 & 4). There is a fee of Rs. 25 for entry as well as exit. The amount u carry inside d parlour gets dou

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Puzzle Time : There are 4 doors in a video game parlour. (door no. 1, 2, 3 & 4). There is a fee of Rs. 25 for entry as well as exit. The amount u carry inside d parlour gets dou      Log On

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Question 694284: Puzzle Time :
There are 4 doors in a video game parlour. (door no. 1, 2, 3 & 4). There is a fee of Rs. 25 for entry as well as exit. The amount u carry inside d parlour gets doubled. U have to get inside d parlour thru door no. 1, come out thru door no. 2, again get inside thru door no. 3 & finally come out thru door no. 4.
Now answer - how much money u should carry while entering door no. 1 such that u have no money left after coming out of door no. 4

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x= amount carried before entering door #1 (in Rs)
after paying Rs. 25 fee to enter, you have x-25.
At this point you are inside the parlour, so your money doubles to
2%28x-25%29.
You pay Rs. 25 to come out thru door no. 2, and again Rs. 25 to get inside thru door no. 3, ending up with
2%28x-25%29-25-25.
At this point you are inside the parlour, so your money doubles to
2%282%28x-25%29-25-25%29.
Then you pay Rs. 25 to come out thru door no. 4 with
Rs. 2%282%28x-25%29-25-25%29-25.
Since you came out with no money left,
2%282%28x-25%29-25-25%29-25=0.
Simplifying:
2%282%28x-25%29-25-25%29-25=0 --> 2%282%28x-25%29-50%29-25=0 --> 2%282x-50-50%29-25=0 --> 2%282x-100%29-25=0 --> 4x-200-25=0 --> 4x-225=0
Solving:
4x-225=0 --> 4x-225%2B225=0%2B225 --> 4x=225 --> 4x%2F4=225%2F4 --> highlight%28x=56.25%29