Question 660366: a caterer os planning a large dinner party for 1001 guests. Each table must seat and equal number of guests, more than 1 guest and fewer than 20. Determine the number of possible table sizes. If the caterers use 11 person tables, how many tables will they need?
Answer by kevwill(135)   (Show Source):
You can put this solution on YOUR website! The prime factorization of 1001 is 7*11*13, so with the constraint that the tables seat between 2 and 19 guests, we can use tables that seat either 7, 11, or 13 guests.
For tables that seat 7, the caterer would need 11*13 = 143 tables.
For tables that seat 11, the caterer would need 7*13 = 91 tables.
For tables that seat 13, the caterer would need 7*11 = 77 tables.
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