SOLUTION: a boy starts walking to school @ 7:30 am at the rate of 3miles per hour, at 7:40am his brother starts for school on his bicycle at 6 miles per hour. When will the boy on the bicycl

Question 659153: a boy starts walking to school @ 7:30 am at the rate of 3miles per hour, at 7:40am his brother starts for school on his bicycle at 6 miles per hour. When will the boy on the bicycle overtake his brother?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
a boy starts walking to school @ 7:30 am at the rate of 3miles per hour, at 7:40am his brother starts for school on his bicycle at 6 miles per hour. When will the boy on the bicycle overtake his brother
**
let x=hrs it takes for boy bicycling to school
10 min=1/6 hr
x+1/6=hrs it takes for boy walking to school
..
distance=speed*travel time (same for both)
6x=3(x+1/6)
6x=3x+3/6
3x=1/2
x=1/6 hr
x+1/6=2/6=1/3 hr
Boy on the bicycle overtakes his brother walking in 1/6 hr or 10 min at 7:50 am
RELATED QUESTIONS
Good day. I'd be really thankful if anyone will be able to help me with this conundrum of (answered by Mathematicians,Theo)

Extreme hardship. Kim starts to walk 3 mi to school at 7:30 A.M. with a temperature of... (answered by ankor@dixie-net.com)

Extreme hardship. Kim starts to walk 3 mi to school at 7:30 A.M. with a temperature of... (answered by stanbon)

Kim starts to walk 3 mi to school at 7:30 A.M. with a temperature of 0�F. Her brother... (answered by galactus)

Kim starts to walk 3 mi to school at 7:30 A.M. with a temperature of 0�F. Her brother... (answered by stanbon)

Santiago is walking to school, which is straight down the road 500m from his home. He... (answered by Edwin McCravy)

Samuel started to walk to school at 6:00 A.M., his brother started to walk at a rate 2... (answered by ankor@dixie-net.com)

Just like my other question, I keep coming with wrong equations, these are my final... (answered by stanbon,Mathtut)

Hamilton High School starts at 8:30 am and finishes at 3:30 pm each day. The number of... (answered by Edwin McCravy)