Question 607683: The perimeter of a rectangle is 94 feet, and the area of the rectangle is 90ft^2. Find the dimensions of the rectangle.
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! Perimeter
P = 2L+2W
94 = 2L+2W
94 - 2L = 2W
2W = -2L + 94
W = -2L/2 + 94/2
W = -L + 47
-------------------------------------------------------
Area
A = LW
A = L(-L + 47)
A = -L^2 + 47L
90 = -L^2 + 47L
0 = -L^2 + 47L - 90
-L^2 + 47L - 90 = 0
L^2 - 47L + 90 = 0
From here, solve the equation for L (using the quadratic formula). Make sure to toss out any negative answers.
Once you get a solution for L, use it to find W.
--------------------------------------------------------------------------------------------------------------
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
--------------------------------------------------------------------------------------------------------------
|
|
|
