SOLUTION: A ball is thrown straight up at an initial velocity of 53 feet per second. In the first 1.5 seconds, it travels 42 feet. The formula s= u+v t

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Question 59088: A ball is thrown straight up at an initial velocity of 53 feet per second. In the first 1.5 seconds, it travels 42 feet. The formula s= u+v t
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represents the vertical distance s that an object travels in t seconds, where u represents the initail velocity of the object an dv represnts the velocity of the object at the end of t seconds. Find the velocity of the ball at the end of 1.5 seconds
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
A ball is thrown straight up at an initial velocity of 53 feet per second. In the first 1.5 seconds, it travels 42 feet. The formula s=%28u%2Bvt%29%2F2
represents the vertical distance s that an object travels in t seconds, where u represents the initail velocity of the object an dv represnts the velocity of the object at the end of t seconds. Find the velocity of the ball at the end of 1.5 seconds
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Solve the formula for v, and plug and chug.
2s=2%28u%2Bvt%29%2F2
2s=u%2Bvt
2s-u=vt
%282s-u%29%2Ft=vt%2Ft
v=%282s-u%29%2Ft u=53, s=42, t=1.5 (units for v:ft/s)
v=%282%2842%29-53%29%2F1.5
v=%2884-53%29%2F1.5
v=31%2F1.5
v=20.6666667 ft/s
v=2.1x10 ft/s rounding off to significatant digits. I don't know how much that matters to you.
Happy Calculating!!!