SOLUTION: Tickets for the father and son breakfast were 2 dollars for fathers and 1.50 dollars for sons. If a total of of 75 tickets were sold for 127.50 dollars, how many fathers and how ma
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Question 566545: Tickets for the father and son breakfast were 2 dollars for fathers and 1.50 dollars for sons. If a total of of 75 tickets were sold for 127.50 dollars, how many fathers and how many sons attended the breakfast?
You can put this solution on YOUR website! Tickets for the father and son breakfast were 2 dollars for fathers and 1.50 dollars for sons. If a total of of 75 tickets were sold for 127.50 dollars, how many fathers and how many sons attended the breakfast?
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Equations:
f + s = 75 tickets
2f+1.5s = 127.50
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Multiply thru the 1st by 2 to get:
2f + 2s = 150
2f +1.5s = 127.50
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Subtract and solve for "s":
0.5s = 22.5
s = 45 (# of son's tickets sold)
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Solve for "f":
f + s = 75
f + 45 = 75
f = 30 (# of father's tickets sold)
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Cheers,
Stan H.
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1 x + 1 y = 75 .............1
2 x + 1.5 y = 127.5 .............2
Eliminate y
multiply (1)by -1.5
Multiply (2) by 1
-1.5 x -1.5 y = -112.5
2 x 1.5 y = 127.5
Add the two equations
0.5 x = 15
/ 0.5
x = 30
plug value of x in (1)
1 x + 1 y = 75
30 + 1 y = 75
1 y = 75 -30
1 y = 45
y = 45
Fathers 30
Sons 45
m.ananth@hotmail.ca
The equation
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1.5x + 2.00(75 - x) = 127.5
We let x represent the number of sons tickets. We know that that the number of father tickets must be (75 - x). We know that the sons tickets are $1.50 each and the fathers tickets are $2.00 each. So we arrange our equation accordingly.
1.5x + 2.00(75 - x) = 127.5.
Using the distributive property we get: 1.5x + 150 - 2x = 127.5
Combining like terms gives us: -.5x=-22.5
Dividing both sides by -.5 gives us: x = 45
45 of sons tickets were sold, to find the amount of fathers we simply subtract 45 from 75 which gives us 30, the amount of fathers tickets sold.