SOLUTION: the electric power generated by a windmill varies jointly with the square of the diameter of the area swept out by the blades and the cube of the wind velocity. If a windmill with
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Question 557553: the electric power generated by a windmill varies jointly with the square of the diameter of the area swept out by the blades and the cube of the wind velocity. If a windmill with 6-foot-diameter blades and a 20-mile-per-hour wind generates 10,823 watts, how much power would be generated if the blades were 10 feet in diameter and the wind speed were 12 miles per hour?
i thought that the solution was P(power) = d^2 (diameter)+ v^3 (wind speed), when i substitute in the values given, 10823= (6*2)^2 + 20^3, i came up with 10823=8144, so not the right equation. can anyone offer any help? Thank you! Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Hint: If the "power generated by a windmill varies jointly with the square of the diameter of the area swept out by the blades and the cube of the wind velocity", then the equation is (note: everything is multiplied together)
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