SOLUTION: Please help me! I think that the answer is 5 seconds, but I don't know. Please show work :) "An object is thrown upward from the top of a 160-foot building with an initial velo
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Question 556643: Please help me! I think that the answer is 5 seconds, but I don't know. Please show work :) "An object is thrown upward from the top of a 160-foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic equation h =16tē + 48t + 160. When will the object hit the ground?"
Thank you in advance for your help!! Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! "An object is thrown upward from the top of a 160-foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic equation h =16tē + 48t + 160. When will the object hit the ground?"
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At 5 seconds, h = 16*25 + 48*5 + 160
h(5) = 800 feet
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h = 0 when it hits the ground.
h =16tē + 48t + 160 = 0
solve for t
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h increases with t, the object will never hit the ground.
