Question 48775: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers. Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! First Integer: i
Second Integer: i + 2
Third Integer: i + 2 + 2 = i + 4
First Integer: i = 16
Second Integer: i + 2 = 18
Third Integer: i + 4 = 20
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