Question 47186: A bricklayer and an electrician together spend 90 hours working on a new house. If the bricklayer earns $12 per hour, the electrician earns $16 an hour, and the owner pays them a total of $1350 for their work, how many hours does each worker spend on the house?
Answer by atif.muhammad(135)   (Show Source):
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A bricklayer and an electrician together spend 90 hours working on a new house. If the bricklayer earns $12 per hour, the electrician earns $16 an hour, and the owner pays them a total of $1350 for their work, how many hours does each worker spend on the house?
Let's say that the bricklayer works for x hrs and the electrician works for y hrs.
A bricklayer and an electrician together spend 90 hours --- (x+y) = 90
Bricklayer earns $12/hr ---- so he earns $12x altogether. (he works for x hrs)
Electrician earns $16/hr ---- so he earns $16y altogether (he works for y hrs)
Altogether, they get paid $1350 ---- Hence, (12x + 16y) = 1350
We now have a pair of simultaneous equations:
(x+y) = 90.....(1)
(12x + 16y) = 1350....(2)
Manipulate (1): x = 90-y...(3)
Substitute (3) into (2)
12(90-y) + 16y = 1350
1080 - 12y + 16y = 1350
4y = 270
y = 67.5 hrs ....(4)
Substitue (4) into (3)
x = 90 - 67.5 = 22.5hrs
Hence, the bricklayer worked for 22.5hrs and the electrician worked for 67.5hrs.
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