SOLUTION: A certain set of data has a mean of 20 and a Standard deviation of 4.5. It is found that two pieces of data have been omitted, one of value 30 and the other of value 25. Find the m

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Question 457977: A certain set of data has a mean of 20 and a Standard deviation of 4.5. It is found that two pieces of data have been omitted, one of value 30 and the other of value 25. Find the mean and S.D of the full 25 pieces of data.
Found 2 solutions by edjones, Edwin McCravy:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
20*23=460
460+30+25=515
515/25=20.6 new mean
.
4.5^2=20.25
20.25*22=445.5 sum of (each data point minus mean)^2
30-20.6=9.4
25-20.6=4.4
9.4^2+4.4^2=107.72
.
445.5+107.72=553.22
sqrt(553.22/24)=4.8 new standard deviation
.
Ed

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
The other tutor's answer for the correct standard deviation is wrong.
Also he used the formula for the standard deviation of a sample, and
this student has informed me that this is to be considered as an 
entire population, not as a sample from a population.

He gave:

4.5^2=20.25
20.25*22=445.5 sum of (each data point minus mean)^2

But that is the sum of each data point minus the mean of the 23)^2
not (the sum of each data point minus the mean of the 25)^2
He incorrectly assumed this was the latter.

It's a bit more complicated than what he did.

He used the definition of the standard deviation
of a sample

s%5E2=%28sum%28%28x-mean%29%5E2%29%2F%28n-1%29%29

but you must use the "shortcut" formula for the
standard deviation of a population 

sigma+=+sqrt%28%28sum%28x%5E2%29%2FN-%28mean%29%5E2%29%29

for the standard deviation instead.

Here is the entire correct problem:

-----------------------------------------------------------------

A certain set of data has a mean of 20 and a Standard deviation of 4.5. It is found that two pieces of data have been omitted, one of value 30 and the other of value 25. Find the mean and S.D of the full 25 pieces of data.
Let sum%28x%2C23%2C%22%22%29 = the unknown sum of the 23 numbers
Let sum%28x%2C25%2C%22%22%29 = the unknown sum of the 25 numbers

Then 

(1)   

Let mean%5B23%5D=+20 be the given mean of the 23 numbers

Let mean%5B25%5D be the unknown mean of the 25 numbers. 

Since mean+=+sum%28x%29%2Fn, then
sum%28x%2C23%2C%22%22%29%22%2F23%22%22%22=%22%2220 

Multiplying both side by 23 gives

sum%28x%2C23%2C%22%22%29=460

From equation (1) above

sum%28x%2C25%2C%22%22%29+=+%28sum%28x%2C23%2C%22%22%29%29%2B55+=+460%2B55+=+515

Therefore

mean%5B25%5D+=+sum%28x%2C25%2C%22%22%29%22%2F25%22%22%22=%22%22515%2F25+=+20.6
 
That's the mean of the 25 numbers, which the other tutor 
calculated correctly.
-----------------------------------
Now we use the short-cut formula for the standard deviation
of a population:

sigma+=+sqrt%28%28sum%28x%5E2%29%2FN-%28mean%29%5E2%29%29

We will use the above formula with both sides squared,
for convenience:

sigma%5E2+=+%28sum%28x%5E2%29%2FN-%28mean%29%5E2%29

Let sigma%5B23%5D=4.5 be the given standard deviation of the 23 numbers

Let sigma%5B25%5D be the unknown standard deviation of the 25 numbers

Let sum%28x%5E2%2C25%2C%22%22%29 be the unknown sum of the squares of the 25 numbers.

Therefore,

(2)  

Using the formula for the 23 numbers:

%28sigma%5B23%5D%29%5E2+=+%28sum%28x%5E2%2C23%2C%22%22%29%29%2F23-%28mean%5B23%5D%29%5E2
 
Substituting given values,

4.5%5E2+=+%28sum%28x%5E2%2C23%2C%22%22%29%29%2F23-20%5E2

20.25+=+%28sum%28x%5E2%2C23%2C%22%22%29%29%2F23-400

420.25+=+%28sum%28x%5E2%2C23%2C%22%22%29%29%2F23

Multiply both sides by 23

9665.75+=+sum%28x%5E2%2C23%2C%22%22%29

From equation (2) above,

sum%28x%5E2%2C25%2C%22%22%29=%28sum%28x%5E2%2C23%29%29%2B1525+=+9665.75%2B1525=11190.75

Using the formula for the 25 numbers,

%28sigma%5B25%5D%29%5E2+=+%28sum%28x%5E2%2C25%2C%22%22%29%29%2F25-%28mean%5B25%5D%29%5E2

Substituting known values

%28sigma%5B25%5D%29%5E2+=+11190.75%2F25-20.6%5E2

%28sigma%5B25%5D%29%5E2+=+447.63-424.36

%28sigma%5B25%5D%29%5E2+=+23.27

sigma%5B25%5D+=+sqrt%2823.27%29

sigma%5B25%5D+=+4.823898838

Edwin