SOLUTION: A dealer sold a certain number of portable TV sets at P6,400 each. The dealer would have taken in as much money had 3 fewer sets been sold at P7,680. How many sets were sold at P6,

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A dealer sold a certain number of portable TV sets at P6,400 each. The dealer would have taken in as much money had 3 fewer sets been sold at P7,680. How many sets were sold at P6,      Log On

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Question 448549: A dealer sold a certain number of portable TV sets at P6,400 each. The dealer would have taken in as much money had 3 fewer sets been sold at P7,680. How many sets were sold at P6,400?
Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
The amount of money taken in by the dealer is the same in both cases.
Let x = the number sold at $6400
The amount taken in at $6400 is:
6400x
And the amount that would have been taken in at $7680 is:
7680(x-3) [3 fewer sets]
Now we set these two equations equal and solve for x:
6400x = 7680(x-3)
1280x = 23040
x = 18
Therefore, 18 sets were sold