Question 447572: The cumulative number of car accidents from 2000 to 2010 can be modeled by the quadratic expression C = -43x² + 1376x + 12040 where x=0 corresponds to 2000, x=1 corresponds to 2001 and so on until x=10 corresponds to 2010. Find the number of cumulative car accidents in 2005.
I don't understand this problem at all, could someone give me a hand, please?
Answer by Edwin McCravy(20054)   (Show Source):
You can put this solution on YOUR website! The cumulative number of car accidents from 2000 to 2010 can be modeled by the quadratic expression C = -43x² + 1376x + 12040 where x=0 corresponds to 2000, x=1 corresponds to 2001 and so on until x=10 corresponds to 2010. Find the number of cumulative car accidents in 2005.
If you substitute x = 0 in C = -43x² + 1376x + 12040 you get the
number of car accidents in the year 2000:
C = -43x² + 1376x + 12040
C = -43(0)² + 1376(0) + 12040
C = 0 + 0 + 12040
C = 12040 accidents in 2000
If you substitute x = 1 in C = -43x² + 1376x + 12040 you get the
number of car accidents in the year 2001:
C = -43x² + 1376x + 12040
C = -43(1)² + 1376(1) + 12040
C = -43 + 1376 + 12040
C = 13373 accidents in 2001
If you substitute x = 2 in C = -43x² + 1376x + 12040 you get the
number of car accidents in the year 2002:
C = -43x² + 1376x + 12040
C = -43(2)² + 1376(2) + 12040
C = -43*4 + 2752 + 12040
C = -52 + 2752 + 12040
C = 14620 accidents in 2002
If you substitute x = 3 in C = -43x² + 1376x + 12040 you get the
number of car accidents in the year 2003:
C = -43x² + 1376x + 12040
C = -43(3)² + 1376(3) + 12040
C = -43*9 + 4128 + 12040
C = -387 + 4128 + 12040
C = 15781 accidents in 2003
If you substitute x = 4 in C = -43x² + 1376x + 12040 you get the
number of car accidents in the year 2004:
C = -43x² + 1376x + 12040
C = -43(4)² + 1376(4) + 12040
C = -43*16 + 5504 + 12040
C = -688 + 5504 + 12040
C = 16856 accidents in 2004
I'll stop there and let you figure out the number of accidents
in the year 2005.
Edwin
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