SOLUTION: A soda machine contains $3.00 in nickels and dimes. If the number of dimes is 5 more than twice the number of nickels, how many coins of each type are there?
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Question 429816: A soda machine contains $3.00 in nickels and dimes. If the number of dimes is 5 more than twice the number of nickels, how many coins of each type are there?
I am completely at a loss for understanding how to solve word problems. Can you help, please? Thank you! Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A soda machine contains $3.00 in nickels and dimes. If the number of dimes is 5 more than twice the number of nickels, how many coins of each type are there?
n = # of nickels
d = # of dimes
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Write down what's given. Don't whine about "word problems"
"Two plus two" is a word problem.
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d = 2n + 5 - # of dimes = 2 times # of nickels plus 5
5*n + 10*d = 300 - n's are 5 cents each, and dimes are 10 cents each. See that?
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d = 2n + 5
5*n + 10*d = 300
Now it's not a word problem.
