SOLUTION: trains a and b are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train b is traveling at 44 miles per hour. Train A passes a sta

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Question 419207: trains a and b are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train b is traveling at 44 miles per hour. Train A passes a station at 4:20 am. If train b passes the same station at 4:50am, at what time will train b catch up to train a''.
what time will train b catch up to train a??

Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The key is to find out how much of a head start train A has.
The difference between 4:20 and 4:50 is .5 hrs
So, A's head start is d1+=+40%2A.5
d1+=+20 mi
Another key is the fact they will be traveling for the same
amount of time after B passes station
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Start a stopwatch when B leaves station
train A:
+d+-+20+=+40t+
train B:
d+=+44t+
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By substitution:
+44t+-+20+=+40t+
+4t+=+20+
+t+=+5+
This says that 5 hrs after B passes station, B catches A
4:50 AM + 5 = 9:50 AM answer
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check answer
d+=+44t
d+=+44%2A5
d+=+220 mi
This is the distance B goes from station
Train A went this distance in 5+%2B+.5+=+5.5 hrs
220+=+40%2A5.5
220+=+220
OK

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
trains a and b are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train b is traveling at 44 miles per hour. Train A passes a station at 4:20 am. If train b passes the same station at 4:50am, at what time will train b catch up to train a''.
what time will train b catch up to train a??
----------------------
Train A is 20 miles ahead at 0450 (40 mph * 0.5 hr)
Train B gains on train A at 4 mph (44- 40)
20 mi/4 mph = 5 hours
0450 + 5 = 0950 or 9:50 AM