SOLUTION: Let the first biker left the ranger station at 'x' hrs. Then by 4 pm he rode for ((4+12) - x) = (16 - x) hrs. Distance traveled by him = {{{10*(16 - x)}}} miles. The second bike

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Let the first biker left the ranger station at 'x' hrs. Then by 4 pm he rode for ((4+12) - x) = (16 - x) hrs. Distance traveled by him = {{{10*(16 - x)}}} miles. The second bike      Log On

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Question 40843: Let the first biker left the ranger station at 'x' hrs.
Then by 4 pm he rode for ((4+12) - x) = (16 - x) hrs.
Distance traveled by him = 10%2A%2816+-+x%29 miles.
The second biker left the ranger station 1 hr after the first biker.
So he traveled for ((16 - x) - 1) = (15 - x) hrs.
Distance traveled by him = 15%2A%2815+-+x%29 miles.
As both bikers met at 4 pm so by then they have travelled equal distances.
So 15%2A%2815+-+x%29+=+10%2A%2816+-+x%29
Solving we get x = 13.
Thus the first biker left the ranger station at 13 hrs or 1 pm.
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