You can put this solution on YOUR website! The sum of the squares of two consecutive integers is 13. Find the integers
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1st: x
2nd: x+1
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Equation:
x^2 + (x+1)^2 = 13
x^2 + x^2 + 2x+1 = 13
2x^2 + 2x -12 = 0
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x^2 + x - 6 = 0
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Factor:
(x+3)(x-2) = 0
x = 2 or x = -3
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If x=2
1st = x = 2
2nd = (x+1) = 3
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If x = -3
1st + x = -3
2nd = (x+1) = -2
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Cheers,
Stan H.