Question 384283: can someone please tell me if either of these answers are correct please.
In 1990, the life expectancy of females was 78.8 years. In 2001, it was 79.8 years. Let F(t) = life expectancy and t = the number of years since 1990.
a) Find a linear function that fits the data.
b) Use the function of Part (a) to estimate the life expectancy in 2010.
Show your work not just the final answer.
F(t) = mt + c
Substituting the first set of figures, F(t) = 78.8 when t = 0 then, 78.8 = (m x 0) + c : c = 78.8
Substituting the second set of figure, F(t) = 79.8 when t = 11 then, 79.8 = 11m + 78.8 : m = 1/11
a) The linear function: F(t) = t/11 + 78 .8
b) 2010, t = 20 so, F(t) = 20/11 + 78.8 = 1.82 + 78.8 = 80.62 years
or
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a) The linear function: F(t) = t/11 + 78 .8
b) 2010, t = 20: so, F(t) = 20/11 + 78.8 = 1.82 + 78.8 = 80.62 years
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In 1990, the life expectancy of females was 78.8 years. In 2001, it was 79.8 years. Let F(t) = life expectancy and t = the number of years since 1990.
a) Find a linear function that fits the data.
b) Use the function of Part (a) to estimate the life expectancy in 2010.
Show your work not just the final answer.
F(t) = mt + c
Substituting the first set of figures, F(t) = 78.8 when t = 0 then, 78.8 = (m x 0) + c : c = 78.8
Substituting the second set of figure, F(t) = 79.8 when t = 11 then, 79.8 = 11m + 78.8 : m = 1/11
a) The linear function: F(t) = t/11 + 78 .8
b) 2010, t = 20 so, F(t) = 20/11 + 78.8 = 1.82 + 78.8 = 80.62 years
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OK
cheers,
Stan H.
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