SOLUTION: if y varies directly as x^2 and inversely as m and y=2 when x=7 and m=9 find y when x=4 and m=6

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Question 376394: if y varies directly as x^2 and inversely as m and y=2 when x=7 and m=9 find y when x=4 and m=6
Found 2 solutions by Alan3354, mananth:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
if y varies directly as x^2 and inversely as m and y=2 when x=7 and m=9 find y when x=4 and m=6
----------
y+=+kx%5E2%2Fm
2+=+k%2A7%5E2%2F9+=+49k%2F9
k = 18/49
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@ x=7, m=9:
y = (18/49)*16/6
y = 48/49

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
y+%28alpha%29x%5E2
..
y%28alpha%29%281%2Fm%29
...
y%28alpha%29%28x%5E2%2Fm%29
...
y+=+%28k%29%2A%28x%5E2%2Fm%29
plug values of a,y,m
2=k%2A%28%287%29%5E2%2F9%29
...
k=%282%2A9%29%2F49
k=18/49
...
x=4, m=6
y=+%2818%2F49%29%2A%28%284%29%5E2%2F6%29
%28highlight+%28y=%2848%2F49%29%29%29
...
m.ananth@hotmail.ca