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| Question 37442:  Vern invested $11,000.  Part was invested at 15% and part at 13%.  If the total interest at the end of the year is $1,610, how much did he invest at 15%?
 Answer by wuwei96815(245)
      (Show Source): 
You can put this solution on YOUR website! Let x = the part invested at 13% and $11,000-x = the part invested at 15%. 
 Then:
 13%x + 15%($11,000-x) = $1,610
 0.13x + 0.15(11,000-x) = 1,610
 0.13x + 1,650 -0.15x = 1,610
 -0.02x = -40
 x = $2,000
 $11,000 -x = $9,000
 
 The answer is that $2,000 was invested at 13% and $9,000 was invested at 15%.
 
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