Question 364308: An airline that flies from Los Angeles to Albuquerque with a stopover in Phoenix charges a fare of $80 to Phoenix and a fare of $120 from Los Angeles to Albuquerque. A total of 220 passengers boarded the plane in Los Angeles, and fares totaled $23,800. How many passengers got off the plane in Phoenix?
Answer by Griffinsdad06(8)   (Show Source):
You can put this solution on YOUR website! Here is what we know 220 boarded the airplane in Los Angeles and they would all have to pay at least $80.
220 X 80 = 17,600
We also know the total of all fares was $23,800.
So lets subtract the minimum amount we know everyone paid ($17,600) from the total amount collected ($23,800)
23,800 - 17,600 = 6,200
Now we know that the remaining people on the plane paid $6,200 to continue to Albuquerque. The cost for the flight from LA to ALB is $120 and the cost from LA to Phoenix is $80. We already said everone paid the $80 so lets subtract the two totals.
120 - 80 = 40
This now means that who ever stayed on to fly to ALB paid an extra $40 and the total of all of those people is $6200. So divide the total by the cost.
6200 divided by 40 = 155
This means 155 people paid the $120. Now just subtract 155 from 220 (total number starting the trip). 65 people got off the airplaine in Phoenix.
Lets check our answer: 65 x $80 = $5,200; 155 x $120 = $18,600;
$5,200 + $18,600 = $23,800.
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