SOLUTION: If an object is thrown upward with an initial velocity of 96ft. per second, its height after 1 sec. is given by h=96t + 16t^2. Find the number of seconds before the object hits the

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Question 340519: If an object is thrown upward with an initial velocity of 96ft. per second, its height after 1 sec. is given by h=96t + 16t^2. Find the number of seconds before the object hits the ground.
Answer by Alan3354(69443) About Me  (Show Source):
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If an object is thrown upward with an initial velocity of 96ft. per second, its height after 1 sec. is given by h=96t + 16t^2. Find the number of seconds before the object hits the ground.
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Your equation is not right, it's h(t) = 96t - 16t^2. If it's +16t^2, it would never stop going up.
h(t) = -16t^2 + 96t
It's a ground level when h(t) = 0
h(t) = -16t^2 + 96t = 0
16t^2 = 96t
t = 0 (at the start)
t = 6 seconds (at impact)