SOLUTION: The perimeter of a rectangle is 182 inches. The length exceeds the width by 21 inches. Find the length and the width.

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Question 323800: The perimeter of a rectangle is 182 inches. The length exceeds the width by 21 inches. Find the length and the width.
Found 2 solutions by msgmhenderson, MathTherapy:
Answer by msgmhenderson(11) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangle is 182 inches. The length exceeds the width by 21 inches. Find the length and the width.
rectangle perimeter formula
2L + 2W
2(L + 21) + 2W = 182
2L + 2W +42 -42 = 182-42
2L +2W = 140
140/4 = 40
35 INCHES
LENGTH IS 35 + 21 = 56
WIDTH IS 35

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangle is 182 inches. The length exceeds the width by 21 inches. Find the length and the width.

Let width be W

Since length exceeds width by 21", its length is: W + 21

Since perimeter = 182, and since perimeter = 2L + 2W, then we'll have:

2(W + 21) + 2W = 182

2W + 42 + 2W = 182

4W = 140

Therefore, W, or width = 140%2F4 or highlight_green%2835%29 inches, and

L, or length = highlight_green%2856%29 ----- (35 + 21)

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Check
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2W + 2L = 182

2(35) + 2(56) = 182

70 + 112 = 182 (TRUE)