SOLUTION: An object is thrown downward from a plane which is 540 feet above the ground. The object is thrown with an initial velocity of 27 ft/sec. The distance traveled by the object in t s
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Question 311559: An object is thrown downward from a plane which is 540 feet above the ground. The object is thrown with an initial velocity of 27 ft/sec. The distance traveled by the object in t seconds is s = 16t2 + 27t, where s is in feet. How long does it take the object to reach the ground? Show your work.
I need help i understand that
540 = 16t^2 + 27t but what is after this I am lost. Please help me if you can Answer by Alan3354(69443) (Show Source):