SOLUTION: A soccer ball is kicked straight up with an initial velocity of 32 ft. per second. Its height above the earth is given by s (t) = -16t^2 + 32t, where, ‘s’ is the height in ft. at a

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Question 307206: A soccer ball is kicked straight up with an initial velocity of 32 ft. per second. Its height above the earth is given by s (t) = -16t^2 + 32t, where, ‘s’ is the height in ft. at any time, ‘t’ seconds.
a. What is the maximum height reached by the ball?
b. How long after it was thrown up the ball reaches its maximum height?

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Hint: Any equation of the form y=at%5E2%2Bbt%2Bc, the max height is reached when t=-b%2F%282a%29 where 'a' is less than zero. Once you have this value of t, plug it in to find the max height.