SOLUTION: Find the measures of the three angles of a triangle if the second is three times the first and the third is twice the second.

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Question 268994: Find the measures of the three angles of a triangle if the second is three times the first and the third is twice the second.
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
b = 3a
c = 2b
a = a
-----
The sum = 180, so we get
a + b + c = 180
or
a + 3a + 6a = 180
10a = 180
a = 18
b = 54
c = 108