SOLUTION: On Friday, the With-It Clothiers sol some jeans at $25 a pair and some shirts at $18 each. receipts for the day totaled $441. On saturday the store priced both items at $20, sol ex

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: On Friday, the With-It Clothiers sol some jeans at $25 a pair and some shirts at $18 each. receipts for the day totaled $441. On saturday the store priced both items at $20, sol ex      Log On

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Question 256062: On Friday, the With-It Clothiers sol some jeans at $25 a pair and some shirts at $18 each. receipts for the day totaled $441. On saturday the store priced both items at $20, sol exactly the same number of each item, and ha receipts of $420. how many pairs of jeans an how many shirts were sold each day?
if some tutor cold help me applying a algebra formula or some this would be very helpful though i can solve the problem i would really want to know how to solve it by algebra means THANKS!

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You're pretty good if you can do it without algebra!
It is given that the same number of both the jeans
and shirts were sold on both days
Let j = number of jeans sold on both days
Let s = number of shirts sold on both days
given:
(1) 25j+%2B+18s+=+441
(2) 20j+%2B+20s+=+420
Now I will multiply both sides of (1) by 4
and both sides of (2) by 5. Then I will
subtract (1) from (2)
(2) 100j+%2B+100s+=+2100
(1) -100j+-+72s+=+1764
28s+=+336
s+=+12
Now plug this result back into either (1) or (2)
(2) 20j+%2B+20s+=+420
20j+%2B+20%2A12+=+420
20j+=+420+-+240
20j+=+180
j+=+9
9 jeans and 12 shirts were sold each day
You can plug these numbers back into original quations
to check