Question 251996: For the next seven years, the St. Louis Cardinals will pay Albert Pujols an average of 14.7 million dollars per year. Twenty-five $20-bills weigh 0.9 ounces. If Albert were to insist on being paid in $20-bills, how many pounds would the $14.7 million weigh? Round to the nearest pound.
A. 1,654 B. 8,148 C. 26,460 D. 33,075 E. 41,344
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! 25 * 20 = 500 dollars.
each set of 25 * 20 dollar bills is worth 500 dollars.
14.7 million divided by 500 = .0294 million sets of 25 * 20 dollar bills.
multiply that by 1 million to get 29400 sets of 25 * 20 dollar bills.
each set weighs .9 ounces.
total weight would be 29400 * .9 = 26460 ounces.
number of ounces in a pound is 16.
total weight would be 26460 / 16 = 1653.75 pounds.
round to the nearest pound to get 1654 pounds.
your answer would be selection A (1654 pounds).
algebraically, you would say:
let x = 1 set of 25 * 20 dollar bills.
500*x = value of each set.
.9*x = weight of each set.
your equation would be:
500*x = 14.7 million
divide both sides by 500 to get:
x = 14.7 milli9on / 500 = .0294 million * 1000000 = 29400
you would solve for the weight by saying
.9*x = .9*29400 = 26460 ounces.
since 16 ounces to a pound, you would then solve for pounds by saying.
26460/16 = 1653.75 pounds.
this rounds to 1654 pounds to the nearest pound.
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