SOLUTION: The height of an object is given by h=-16t^2+v^0t+h^0 ft. after t seconds, where v^0 is the initial velocity of the object in ft./sec and h^0 is the initial height of the object in
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Question 215961This question is from textbook
: The height of an object is given by h=-16t^2+v^0t+h^0 ft. after t seconds, where v^0 is the initial velocity of the object in ft./sec and h^0 is the initial height of the object in feet.
An object is thrown upwards from the top of a 650ft. building at an initial velocity of 64 ft./sec.
a) For what t>0 is the object feet from the ground?
b)For what t.0 is the object on the ground? This question is from textbook
You can put this solution on YOUR website! The height of an object is given by h=-16t^2+v^0t+h^0 ft. after t seconds, where v^0 is the initial velocity of the object in ft./sec and h^0 is the initial height of the object in feet.
An object is thrown upwards from the top of a 650ft. building at an initial velocity of 64 ft./sec.
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h(t) = -16t^2 + 64t + 650
a) For what t>0 is the object feet from the ground?
?? How many feet?
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b)For what t.0 is the object on the ground?
-16t^2 + 64t + 650 = 0
-8t^2 + 32t + 325 = 0
