SOLUTION: Quadratics and complex numbers:Analyzing Quadratics in vertex form f(x)=(x-h)^2 Question: The sides of a pool are given by x + 10 feet and x - 11 feet. If the area of the

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Question 214721: Quadratics and complex numbers:Analyzing Quadratics in vertex form f(x)=(x-h)^2

Question:
The sides of a pool are given by x + 10 feet and x - 11 feet. If the area of the pool is 490 square feet, what are the dimensions of the pool?

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
AreaOfrectangle+=+Length+%2A+Width
Given dimensions are x+%2B+10 feet and x+-+11 feet and area = 490 square feet
%28x%2B10%29%2A%28x-11%29+=+490
x%5E2+-+11x+%2B+10x+-+110+=+490
x%5E2+-x+-110+=+490
x%5E2+-x+-+600+=+0
%28x-25%29%28x%2B24%29+=+0
x = 25
If x - 25, then x+10 = 35 and x-11 = 14